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Mathematics 16 Online
OpenStudy (anonymous):

15x3-24x2+5x-8= factor by grouping

OpenStudy (anonymous):

\[15x^3-24x^2+5x-8\] \[3x^2(5x-8) +1(5x-8)\] \[(3x^2+1)(5x-8)\]

OpenStudy (anonymous):

(15x^3-5x)-24x^2-8 5x(3x^2-1)-8(3x^2-1) (5x-8)(3x^2-1)

OpenStudy (anonymous):

Oh, wow I thought it was -5x, so (5x-8)(3x^2+1)

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