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Find the volume of the solid obtained by rotating the region bounded by the curves y=4+sec(3x) ,between -pi/9 and pi/9 , y=6 about the line y-4
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\[\pi\int_{-\frac{\pi}{9}}^{\frac{\pi}{9}}(4+sec(3x))dx\]
is that your final answer?
nope
about the line y = 4?
yep
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\[\pi\int_{-\frac{\pi}{9}}^{\frac{\pi}{9}}((4+sec(3x))^2-(4^2))dx\]
i got all those steps i need to see what your final answer is cos i keep getting my final answer wrong
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