Question

how would you solve √x2-x-6=x+3 (the xsquared and x and 6 are all under the radical

Answer 1

squaring on both sides
=> x2 - x - 6 = x2 + 6x + 9
=> 7x = -15
=> x = -15/7

Answer 2

the answer asks for a solution set so would i just write -15/7?

Answer 3

\[\left\{x such that x=-.15/7 \right\}\]
they are probably asking for set builder notation.
There is a symbol for such that but I did not find it in the equation menu.

Answer 4

it just asks what is the solution set and to separate my answer with a comma