Question

can someone show me how to work out x^2-9 over x^2 times x^2-3x over x^2+x-12

Answer 1

\[\frac{x^2-9}{x^2} \times \frac{x^2-3x}{(x-3) (x+4) }\]

Answer 2

\[\frac{(x-3)(x+3)}{x^2} \times \frac{x^2-3x}{(x-3) (x+4) }\]