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Mathematics 16 Online
OpenStudy (anonymous):

x2-25x+24=0 solution set?

OpenStudy (anonymous):

factor as \[(x-1)(x-24)=0\] then procede

OpenStudy (precal):

x=24 and x=1 Factor or use the quadratic formula

OpenStudy (anonymous):

(x-24)(x-1)=0 ===> x=23 or x=1

OpenStudy (precal):

raheen really x=23

OpenStudy (anonymous):

sorry I mean 24 mistyping

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