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OpenStudy (anonymous):
x2-25x+24=0 solution set?
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OpenStudy (anonymous):
factor as \[(x-1)(x-24)=0\] then procede
OpenStudy (precal):
x=24 and x=1 Factor or use the quadratic formula
OpenStudy (anonymous):
(x-24)(x-1)=0 ===> x=23 or x=1
OpenStudy (precal):
raheen really x=23
OpenStudy (anonymous):
sorry I mean 24 mistyping
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