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Square root of (x+deltaX)+ 2 - square root of (x-2)/ delta x
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\[\sqrt{x+\Delta x}+2-\sqrt{\frac{x-2}{\Delta x}}\]??
no the (delta)x is over both sqaure roots only
maybe \[\frac{\sqrt{x+\Delta x}+2-\sqrt{x-2}}{\Delta x}\]
yes but the +2 is also under the square root
\[\sqrt{(x+\Delta x)+2} - \sqrt{x+2} / \Delta x\]
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