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6c^2+13c+6 factor
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(3c + 2 )(2c + 3 )
6c^2 + 13c + 6 = 6c^2 + 9c + 4c + 6 = 3c(2c+ 3) + 2(2c + 3) (2c+3) (3c +2)
Utilize the quadratic formula to factor if you are stuck. For a given quadratic expression of the form \[ax^2+bx^2+c\]It can be factored via\[a\left(x-\dfrac{-b + \sqrt{b^2-4ac}}{2a}\right)\left(x-\dfrac{-b-\sqrt{b^2-4ac}}{2a}\right)\]
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