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how can u simplify 1-x3/ 1-x
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= x^2+x+1
ix this ( 1 - x^3) / (1 - x) ?
factor thenumerator using two cubed differnce identity then cancel with the denomerator
yes it is 1-x^3/ 1-x
then raheen's answer is correct
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how did he solve it
well 1 - x^3 = (1-x)(x^2 + x +1) and the 1-x cancels with the 1-x on the top leaving only the second bracket x^2 + x +1)
thank u :)
yw
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