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sqrt{x+2} = 6 - sqrt{7x+2}
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\[\sqrt{x+2} = 6 - \sqrt{7x+2}\]
square bothe sides (x+2)=36-12sqrt(7x+2)+(7x+2) x+2-36-7x-2=-12sqrt(7x+2) -36-6x=-12sqrt(7x+2) /:(-6) 6+x=2sqrt(7x+2) square both sides 36+12x+x2=4(7x+2) 36+12x+x2 -28x-8=0 x2 -16x +28 =0
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