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Mathematics 18 Online
OpenStudy (anonymous):

(2sin^2)(x)(sin)(x)+1=0 0≤x<2π

OpenStudy (anonymous):

wow, what's this?

OpenStudy (anonymous):

homework lol

OpenStudy (anonymous):

\[2 \text{Sin}^2[x]\text{Sin}[x]+1=0\] right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[2 \text{Sin}^3[x]+1=0\]

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