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log(x2-2x+1)= log(x2+4x-5) i need solution
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None. I think that's what it is. No solutions exist.
but this is the question
x^2-2x+1=x^2+4x-5 ==> 6x=6 ==> x=1
oh yeah that's right, the log would cancel. Right?
exactly, you may cancel
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too much calculus tonight....lol
thnxx alot @raheen
lol
any time @jinausa
sorry for my horrible response haha.i know better too thats the sad part
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thtss okkk@lawnphysics
\[\log(x^2-2x+1)= \log(x^2+4x-5)\]\[x^2-2x+1=x^2+4x-5\]\[6x=6\]\[x=1\]
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