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this should be my last question integral of [1/(y lny)]dy
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\[\int\frac{dy}{y\ln{y}}=\int\frac{d(\ln{y})}{\ln{y}}=\ln{\ln{y}}+C\]
wait, what happened?
\[\text{Let }u=\ln(y)\] \[du=\frac{1}{y}dy\] \[\int \frac{1}{y\ln(y)}dy=\int\frac{1}{u}du=\ln|u|+c=\ln|\ln(y)|+c\]
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