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y varies directly as the square of x. When x = 1, y = 3. What is the value of y when x = 3?
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y = kx^2 k = 3 y = (3)*9 = 27
y = kx^2 find k
27
thankk uuu :D
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amistre, y varies with x squared, not just with x.
.... lol, well that changes things a bit ;)
indeed it does :)
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