In a certain right triangle, the one leg is two times longer than the other leg and the the hypoteneuse is four feet longer than the shorter leg. If x represents the length of the shorter leg, then by the Pythagorean Theorem this problem translates to which equation below:

a. x2 + 2x2 =4x2

b. x2 + (x + 4)2 =2x2

c. x2 + (x + 4)2 =4x2

d. x2 + 2x2 =(x + 4)2

e. x2 + 4x2 =(x + 4)2

Question

In a certain right triangle, the one leg is two times longer than the other leg and the the hypoteneuse is four feet longer than the shorter leg. If x represents the length of the shorter leg, then by the Pythagorean Theorem this problem translates to which equation below:

a. x2 + 2x2 =4x2

b. x2 + (x + 4)2 =2x2

c. x2 + (x + 4)2 =4x2

d. x2 + 2x2 =(x + 4)2

e. x2 + 4x2 =(x + 4)2

sriram · Answer

E

anonymous · Answer

could you explain how you get that?

sriram · Answer

the two legs which aren't hypotnuseare 
x and 2x
hypotnuse=x+4
hencex^2+(2x)^2=(x+4)^2
giving 
x^2+4x^2=(x+4)^2

anonymous · Answer

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