Question

can someone help me evaluate this limit (if it exists):
lim [abs(x-3)/(x-3)]
x->3

Answer 1

lim x-3..... -(x-3)/x-3=-1 and limx--3+ (x-3)/(x-3)=1

Answer 2

im not sure im following what you sent

Answer 3

lim x-> does not exist since \[\lim_{x \uparrow 3} \neq \lim_{x \downarrow 3}\]

Answer 4

http://www.wolframalpha.com/input/?i=lim+%5Babs%28x-3%29%2F%28x-3%29%5D+x+goes+3

Answer 5

thanks!