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Mathematics 25 Online
OpenStudy (konradzuse):

evaluate each integral (x) / (4x^2 + 2) dx

OpenStudy (anonymous):

\[u=4x^{2}+2 ..........du=8x dx\]

OpenStudy (anonymous):

\[1/8 \int\limits_{}^{} \frac{1}{u}du\]

OpenStudy (anonymous):

1/8 ln(4x^2+2) +C

OpenStudy (konradzuse):

I made a mistake it's +1 not 2, thanks for the help!

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