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evaluate each integral (x) / (4x^2 + 2) dx
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\[u=4x^{2}+2 ..........du=8x dx\]
\[1/8 \int\limits_{}^{} \frac{1}{u}du\]
1/8 ln(4x^2+2) +C
I made a mistake it's +1 not 2, thanks for the help!
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