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evaluate each integral (cos2x) / (1+sin2x) dx
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u=1+sin2x \[du=2\cos2x dx\]
\[1/2 \int\limits_{}^{} \frac{1}{u}du =1/2 \ln(u)+C =1/2 \ln(1+\sin2x)+C\]
i think it is necessary here to insert | | instead of ( )
but great job john
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