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Mathematics 19 Online
OpenStudy (anonymous):

given that p=4 and q=6, calculate please, simplify where possible the value of: 3p^2+q^3

OpenStudy (anonymous):

264

OpenStudy (anonymous):

can you explain please

OpenStudy (anonymous):

3(4)^2+(6)^3

OpenStudy (stormfire1):

\[3(4^2) + 6^3\]\[3(16)+216\]\[48+216=264\]

OpenStudy (anonymous):

four to the second power and 6 to the third power. Multiply whatever four the the second power is by 3 and add whatever 6 to the third power is to that.

OpenStudy (anonymous):

Take four the the second power and take 6 to the second power I mean.

OpenStudy (anonymous):

augh 6 to the third power

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