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given that p=4 and q=6, calculate please, simplify where possible the value of: 3p^2+q^3
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264
can you explain please
3(4)^2+(6)^3
\[3(4^2) + 6^3\]\[3(16)+216\]\[48+216=264\]
four to the second power and 6 to the third power. Multiply whatever four the the second power is by 3 and add whatever 6 to the third power is to that.
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Take four the the second power and take 6 to the second power I mean.
augh 6 to the third power
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