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What angle does the line P(7,-4) and Q(1,6) make with the positive x-axis?
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aractan(10/-6)
(7,-4) -(1, 6) ------- <6,10> = 2<3,5>
<3,5> <1,0> ------ 3+0 = 3 \[cos(a)=\frac{3}{\sqrt{34}}\] \[cos^{-1}(\frac{3}{\sqrt{34}})\ :)\]
just to be different lol
The answer in the back of the book says it's 122
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i dropped a negative, doh!
it should be about 59 degrees or so
it is in 2nd quardant take arc tan(10/6) then 180-arc tan(10/6)
thats better
Since it's in the 2nd quadant you have to subtract 180?
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