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g(f(x))??? f(x)= x-5 g=x squared
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g(f(x)=x-5
(x-5)^2
didnt see the squared :$
\[g \left( f(x) \right)=g \left( x-5 \right)=(x-5)^2\]
you might want to expand the binomial\[x^2-10x+25\]
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is it x^2(x-5) and do i just destribute?
the rule of association for the function f, which is x-5 is substituted in the rule from function g, which is x^2
i think it is x^3-5x^2 correct me if im wrong
that is incorrect. the answer in two different forms are in my first and second posts:\[(x-5)^2=x^2-10x+25\]
ok thank you
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ur welcome
hey 1 more thing
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