Question

find values of b such that the vectors (-11,b,2) and (b,b^2,b) are perpendicular

Answer 1

-11b+b^3+2b = 0
b^3 = 9b
b^2= 9
b=+/- 3

Answer 2

how do u know when its going to be perpendicular?

Answer 3

dot product=0

Answer 4

\[b^3-9b=b(b^2-9)=0 => b=0, b=3, or b=-3\]

Answer 5

i for got about the 0

Answer 6

:)

Answer 7

thanks ya'll :)