Question

Find an equation for the tangent line at the
point P (−2, f(−2)) on the graph of
f(x) = 3x^2 + 2x + 4

Answer 1

f(-2)=3(-2)^2+2(-2)+4=12
point P(-2,12)

Answer 2

1. y − 10x − 8 = 0 2. y + 10x + 16 = 0
3. y - 10x + 16 = 0
4. y + 10x + 8 = 0
5. y + 10x - 16 = 0
6. y - 10x + 8 = 0

These are the answer choices

Answer 3

you draw the line of point (-2,12) and then find the slopes and then find the formula