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find the zeros of the function algebraically. f(x)= 2x^2-9/(3-x)
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f(0)=x
(2x+3)(2x-3)/(3-x) = 0 (2x+3)(2x-3) = 0 2x+3=0 2x=-3 x=-3/2 similarly 2x=3 x=3/2 zerios are 3/2 and -3/2
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