(40*40*40 – 31*31*31)/(40*40+40*31+31*31) ?
\[(40^3-31^3)/(40^2+(40(31) + (31)^3)\] \[a^3-b^3=(a-b)(a^2+ab+b^2)\] hence ::::::::::::; \[40^3-31^3 = (40-31)(40^2+(40)(31) + 31^2)\] now :::::::::::::::::; \[{(9(40^2)+40(31) +31^2)/(40^2+40(31)+31^2)}\] \[9\]
got it aman
yes thank u i also find this answer on google. but i did'nt able to understand dis....
ok aman no problem a medal would be great
well r u on facebook ?
yes
can u give me ur profile link of facebook >?
at dis time i m in office so i did'nt able to open the facebook
ok well what is ur name there , any email id or any thing else
plz send me your profilr link on my mail ie singhaman2055@gmail.com i will join from there
k aman
well please give me a medal
did u send ur link
okies i will send u req in night
thanx a lot now i able to understand the problem
k
Join our real-time social learning platform and learn together with your friends!