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Mathematics 17 Online
OpenStudy (anonymous):

(40*40*40 – 31*31*31)/(40*40+40*31+31*31) ?

OpenStudy (anonymous):

\[(40^3-31^3)/(40^2+(40(31) + (31)^3)\] \[a^3-b^3=(a-b)(a^2+ab+b^2)\] hence ::::::::::::; \[40^3-31^3 = (40-31)(40^2+(40)(31) + 31^2)\] now :::::::::::::::::; \[{(9(40^2)+40(31) +31^2)/(40^2+40(31)+31^2)}\] \[9\]

OpenStudy (anonymous):

got it aman

OpenStudy (anonymous):

yes thank u i also find this answer on google. but i did'nt able to understand dis....

OpenStudy (anonymous):

ok aman no problem a medal would be great

OpenStudy (anonymous):

well r u on facebook ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

can u give me ur profile link of facebook >?

OpenStudy (anonymous):

at dis time i m in office so i did'nt able to open the facebook

OpenStudy (anonymous):

ok well what is ur name there , any email id or any thing else

OpenStudy (anonymous):

plz send me your profilr link on my mail ie singhaman2055@gmail.com i will join from there

OpenStudy (anonymous):

k aman

OpenStudy (anonymous):

well please give me a medal

OpenStudy (anonymous):

did u send ur link

OpenStudy (anonymous):

https://www.facebook.com/kushashwaravi.shrimali

OpenStudy (anonymous):

okies i will send u req in night

OpenStudy (anonymous):

thanx a lot now i able to understand the problem

OpenStudy (anonymous):

k

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