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OpenStudy (anonymous):
(40*40*40 – 31*31*31)/(40*40+40*31+31*31) ?
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OpenStudy (anonymous):
\[(40^3-31^3)/(40^2+(40(31) + (31)^3)\]
\[a^3-b^3=(a-b)(a^2+ab+b^2)\]
hence ::::::::::::;
\[40^3-31^3 = (40-31)(40^2+(40)(31) + 31^2)\]
now :::::::::::::::::;
\[{(9(40^2)+40(31) +31^2)/(40^2+40(31)+31^2)}\]
\[9\]
OpenStudy (anonymous):
got it aman
OpenStudy (anonymous):
yes thank u
i also find this answer on google.
but i did'nt able to understand dis....
OpenStudy (anonymous):
ok aman no problem a medal would be great
OpenStudy (anonymous):
well r u on facebook ?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
can u give me ur profile link of facebook >?
OpenStudy (anonymous):
at dis time i m in office so i did'nt able to open the facebook
OpenStudy (anonymous):
ok well what is ur name there , any email id or any thing else
OpenStudy (anonymous):
plz send me your profilr link on my mail ie singhaman2055@gmail.com i will join from there
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OpenStudy (anonymous):
k aman
OpenStudy (anonymous):
well please give me a medal
OpenStudy (anonymous):
did u send ur link
OpenStudy (anonymous):
okies i will send u req in night
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OpenStudy (anonymous):
thanx a lot now i able to understand the problem
OpenStudy (anonymous):
k
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