Question

Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form.

Answer 1

y = -4x+5

Answer 2

since its perpindicular the slope is the negative reciprocal of 4
= \[\frac{-1}{4}\]
so the equation
y=mx+b
\[-3=\frac{-1}{4}(2)+b\]\[-12=-2+b\]\[b=-10\]
now we have
\[y=\frac{-1}{4}x-10\]
in standard form it is
\[x+4y+40=0\]

Answer 3

oooops, i forgot the reciprocal, my bad,

Answer 4

hmmmmmm