A 250-N crate is pulled along a horizontal sidewalk at a constant speed by a rope which makes an angle of 40 degrees with the sidewalk. If a force is 150-N is applied on the rope what is the coefficient of sliding friction?

Question

anonymous · Answer

μmg=fcosθ
μ=fcos40/mg
u = 150\cos40/250 \]
μ=(3/5)cos40=0.459

moongazer · Answer

http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e6f31440b8beaebb29b8ea7

moongazer · Answer

please answer my last question there :)