Question

Long divide the following:
P(x) = x^2 / (x^2 - 1)

Answer 1

Attempt:
How many times does x^2 go into x^2? One time, so then I get:
1
x^2 - 1 | x^2
x^2
0

Answer 2

Now what do I do ?

Answer 3

From that, we have \(P(x)=1+\frac{1}{x^2-1}\).