Question

how much of an alloy that is 40% copper should be mixed with 600 ounces of an alloy that is 70% copper in order to get an alloy that is 50% copper? ans in ounces pls

Answer 1

Y oz alloy1 gives .40(Y) oz Cu
600 oz alloy2 gives .70(600)=420 oz Cu
Total Cu = 420+.40Y
Total weight = 600+Y
%Cu =( 420+.40Y)/(600+Y) = .50
.5(600+Y)=420+.40Y
.1Y=120
Y=1200 oz