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limit of 4-sqr.root(x)/ (x-16).... x is appoaching 16
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\[\lim_{x \rightarrow 16}(4-\sqrt{x})/(x-16)?\] Is that your equation?
yep!
the limit is equal to the HA, so... -1/8 and here is the work becasue I am to lazy to right it out. :) http://www.wolframalpha.com/input/?i=lim+as+x+approaches+16+of+%5B4-sqrt%28x%29%5D%2F%28x-16%29
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thanks soooo much!
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