Question

The distance (in miles) traveled when driving at a certain speed s for 23 hours,
then driving miles/hour faster for another hour.
Express the distance in terms of s.
We'll do it in parts:

the distance traveled when driving at s mph for 23 hours is the expression __________ .

ADDED to that distance is driving 1 hour at 14 mph FASTER,
so the expression to be added is _______.

The final answer (expression) then is __________.

Please help me on this one!

Answer 1

first one is
\[D=23s\]

Answer 2

14 mph faster is
\[23+14=37\] and so you add
\[D=23s+37\]

Answer 3

so.... s=37?