Question

I need help finding the inverse of f(x) = 7 + sqrt(2 x - 5)

Answer 1

so far I have \[y ^{2}-7^{2}=2x-5\]

Answer 2

Let f(x) be y (for making it easy )
y - 7 =sqrt(2x-5)
(y-7)^2 =2x - 5
\[\frac{(y-7)^2+5}{2} =x \]
\[f^{-1}(x)= \frac{(x-7)^2+5 }{2}\]