Question

how to divide monomials??

Answer 1

cancel out the common terms

Answer 2

..???

Answer 3

\[5x ^{2}/3x\]
cancel one x from numerator and denominator
5x/3

Answer 4

\[5x^2/3x\]
\[5(x*x) / 3x\]
\[5x/3\]

Answer 5

tnx :D

Answer 6

my please lilyss any more questions u have

Answer 7

can you pls answer this..

-20a2b3c / 8a2b3c

Answer 8

kush is not here

Answer 9

?????????????

Answer 10

\[\frac{20\cancel{a^2b^3c}}{8\cancel{a^2b^3c}}=\]\[\frac{5}{2}=2.5\]

Answer 11

how do you do dat??

Answer 12

\[\frac{20a^2b^3c}{8a^2b^3c}=\]\[\frac{20}{8}\times \frac{\cancel { a^2}}{\cancel{a^2}}\times \frac{\cancel{b^3}}{\cancel{b^3}}\times \frac{\cancel{c}}{\cancel{c}}=\]\[\frac{4\times5}{4\times2}\times1\times1\times1=\]\[\frac{\cancel{4}}{\cancel{4}}\times \frac{5}{2}=\]\[1 \times \frac{5}{2}\]\[\frac{5}{2}=2.5\]