Question

2-xz=0
-4yz-3=0
-x^2-2y^2+4=0
solve for x and y

Answer 1

xz=2
so x =2/z
4yz = -3
so y= -3/4z

substitute it in equation
x^2 + 2y^2 = 4

and find z

then similarly find x and y