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OpenStudy (anonymous):
Factor 5x^2 + 35X
Please explain how to check by multiplication, thanks!
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OpenStudy (amistre64):
check by multilplication? umm ... multiply them back after you factor?
OpenStudy (amistre64):
5x (x^2+7) is the factors right?
OpenStudy (amistre64):
x^2 + 7
5x
---------
5x^3 +35x
OpenStudy (anonymous):
I got 5x(x+7) ?????
OpenStudy (anonymous):
I do not understand how you check it by multiplication ?
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OpenStudy (amistre64):
if i asked you to multiply 27 by 3, what would you do?
OpenStudy (amistre64):
its the same process. multiplication doesnt cahnge simply becasue we rewrite how a number looks
OpenStudy (amistre64):
20+7 times 3
OpenStudy (amistre64):
if you got: 5x(x+7), lets multiply them back together to check it out
x +7
5x
---------
5x^2 +35x
OpenStudy (anonymous):
Okay thanks, I understand now. I will need to practice this a lil more, I guess I over thought it
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OpenStudy (amistre64):
lol ... it was the form that threw you most likely. Multiplication itself is just multiplication :)
OpenStudy (anonymous):
Lol yea :)
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