Question

find the equation of the line tangent to the function at the given point. f(x)=5x^2 at x=10

Answer 1

Find the slope:
f'(x)=10x
f'(x)= 10*10 = 100
Solve for y:
\[f(x) = 5x ^{2} = 5 * 100 = 500\]

y = 100x-500