Question

solve for x 2x^4+6x^3-50x^2-150x=0

Answer 1

2x^3(x + 3) - 50x(x + 3) = 0
(x+3)(2x^3 -50x) = 0
(x+3)(2x(x^2 - 50) = 0
x = 0 or -3
also x^2 = 50
x = sqrt50 or -sqrt50

Answer 2

summary zeros at
x = 0 , -3 , 7.071, - 7.071.

Answer 3

hold on araceli - theres an error on line 3
(x+3)(2x(x^2 - 25) = 0 its 25 not 50

so x^2 = 50 so x = 5 or -5

roots are 0, -3 , 5 and -5.

Answer 4

correct this time

Answer 5

sorry about that