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x+2 = RADICAL (7 + 2x)
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(x+2)(x+2) = 7 +2x Sp;ve.
SOLVE*
YES! Solve for x
x^2 + 4x + 4 -2x -7 = 0 x^2 + 2x -3 = 0
(x+2)^2=7+2x ===> x^2+2x-3=0 ===> (x+3)(x-1)=0 ===> x--3 or x=1
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I get (x+1) (x-3), but when I plug them back in, nothing seems to work! HELP?
I got x=-1 and x+3, but they don't seem to be solutions - please check them for me too! I'm losing my mind!
1, -3 Solutions.
but, they don't work when you plug them back in to the original equation do they? I couldn't get them to work
yes they do.
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try it.
3 = 3
both of them?
the second one is messed up!
-1 = 1
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