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OpenStudy (anonymous):
heeellpppp pleasseeeee !
3(x+2)^2-10(x+6)-8=0
expand and collect like terms in the original equation , and solve the resulting equation for x??
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OpenStudy (anonymous):
3(x+2)^2-10(x+6)-8
3(x^2+4x+4)-10x-60-8
3x^2+12x+12-10x-68
3x^2+2x-56
(3x+14)(x-4)
x=-14/3,4
OpenStudy (anonymous):
Sorry for how long it took, I kept making mistakes. My numbers kept running together bee n looking at computer for too long. lol
OpenStudy (anonymous):
thanks so much and its ok i just needed the help i couldnt figure it out.
OpenStudy (anonymous):
-14 over 3?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
something wrong
OpenStudy (anonymous):
hmmm...im not sure where is.
OpenStudy (anonymous):
me neither
OpenStudy (anonymous):
I am not sure what is wrong. What I copied and solved is correct. I checked multiple times. Did you maybe copy it wrong?
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OpenStudy (anonymous):
yeah i did sorry its supposed to be 3(x+6)^2-10(x+6)-8=0
OpenStudy (anonymous):
can you factor out (x+6)?
OpenStudy (anonymous):
ahh i see the problem, what you origianlly wrote had a 2 where 6 is
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
3(x+6)^2-10(x+6)-8
3(x^2+12x+36)-10x-60-8
3x^2+36x+108-10x-68
3x^+26x+40
(3x+20)(x+2)
x=-20/3,-2
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OpenStudy (anonymous):
sorry about that
OpenStudy (anonymous):
haha it is not a problem
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