Question

Find 4 consecutive odd integers with a sum of 184.

Answer 1

\[n+n+2+n+4+n+6=184\]
\[4n+12=184\] then done right?

Answer 2

isnt that even integers?

Answer 3

184-12=172/4=43

Answer 4

43+45+47+49

Answer 5

43+43+43+43 does not equal 184

Answer 6

x- 1st number
(x)+(x+2)+(x+4)+(x+6)=184
4x+12=184
4x=172
x=43
the nos are 43,45,47,49

Answer 7

THanks very much

Answer 8

ur welcome