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Solve for x 64(x^2) = 25
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\[(8x-5)(8x+5)=0\]
divide by 64, square root (25/64)
\[x=\frac{5}{8}\]\[x=\frac{-5}{8}\]
x^2 =25/64 Square root 25/64 =0.625
I'm thinking 5/8
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u fractorise it difference between two squares (8x-5)(8x+5)=0
if you see my above reply, it is \[\sqrt{25/64}\] which leads to \[\pm5/8\]
+5/8, -5/8
64 x^2-25 = 0 so, x = -5/8 or x = 5/8
thanks..!! i am the best..##
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