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OpenStudy (anonymous):
let g(X) = abs(cosx-1) the maximum value attained by g on the closed interval [0, 2pi] is for x equal to a. -1 b. 0 c. pi/2 d. 2 e. pi
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OpenStudy (anonymous):
The answer is pi
OpenStudy (anonymous):
cosx-1 is negative in [0, 2pi] thus g(x)=-(cosx-1)=1-cosx derived it g'(x)=-senx=0 it entails x=pi
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