Question

Help!!! :P Solve by factoring:
3x^2-24x-48=0
Show work please?? Thank you. :)

Answer 1

\[3(x ^{2}-8x-16)=0\]
\[(x ^{2}-8x-16)=0\]
\[x=(-b \pm \sqrt{b ^{2}-4ac})/2a\]

Answer 2

Thus:
\[x=4\pm4\sqrt{2}\]