Question

Using the concept of slope, find t such that the three points are collinear: (-3,3), (t,-1),(8,6)

Answer 1

t=-53/3

Answer 2

How?

Answer 3

To find the slope you use:\[m=(y _{2}-y _{1})/(x _{2}-x _{1})\]
Using the ordered pairs you have:
(6-3/8-3)=3/5

Answer 4

Now we find the intercept using a point.
y=mx+b; (3/5)3+b=3
9+5b=15
b=6/5

Answer 5

Sorry, I missed a (-) sign in the problem:slope should be:
(6-3)/(8-(-3))=3/11!

Answer 6

x:8 as 7:3 8(7)/3 = 56/3 ... maybe? lol

Answer 7

So (3/11)(3) +b = 3 ?

Answer 8

you're losing the sign too!
b then becomes
y=mx+b; (3/11)(-3)+b=3
b=42/11

Answer 9

(3/11)t+(4/11)2=-1
t=-53/3

Answer 10

Sorry for the detour!

Answer 11

(-3,3) (t,-1) (8,6)
+3-3 +3-3 +3-3
------------------
(0,0) <t+3,-4> <11,3>

-3/4<t+3,-4>= <11,3>

-3t-9
------ = 11
4

-3t-9 = 44

-3t = 44+9

t = -53/3 .... better

Answer 12

i forgot how to subtract 6-3 :)

Answer 13

Amistre how did you get -3/4 on the 4th line?

Answer 14

OH nvm i think i get it now thanx for explaining guys :D

Answer 15

i needed my vectors to match; so a scaled the unknown my -3/4