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Help me solve this differential equation for v(t)!
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\[\dfrac{dv}{dt}+bm_0e^{-\gamma t}v+(g-u\gamma)=0\]b, m_0, γ, g, and u are constants (γ is probably negative, with the other ones positive).
take \((g-u\gamma)\) to the right hand side find an integrating factor \(R(t)=e^{\int bm_0e^{-\gamma t} \text dt}\) \[\frac{\text{d}}{\text d t}\left(R(t)v\right)=R(t)(g-u\gamma)\]
you dont have to include the constant of integration in the integrating factor, you'll get one later down the line.
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