Question

Given f(x) = 2x and g(x) =4x-3, show that (f^-1 of g^-1)(x) = (g of f)^-1 (x)

Answer 1

f^-1---> x=2y--->y=x/2
g^-1--->x=4y-3--->y=(x+3)/4
f^-1 o g^-1=(x+3)/8
(gof)=8x-3
(gof)^-1--->x=8y-3--->y=(x+3)/8
proved!!! ^_^

Answer 2

Thanks so much!!

Answer 3

uw :)