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x^4-16^2+15=0 please solve
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x^2-241=0 x^2=241 x=+-sqr241
\[x=\sqrt[4]{271}\]
i'm sorry! i meant x^4-16x^2+15=0
4.0573485964548730093221785586954571686819749139665696236896
please factor :D
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(x-1) (x+1) (x^2-15) = 0
sorry but could you explain how you got that?
x^4 - 16x^2 + 15=0 possible factors of x^4: x^2 &x^2 possible factors of 15: -15 & -1 cross multiply and add = -16x^2 (middle term) -15|dw:1316171009132:dw|
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