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Mathematics 9 Online
OpenStudy (anonymous):

b^2-aw/b^2-a^2-w+b/a+b=w-a/b-a

OpenStudy (anonymous):

what is ur question?

OpenStudy (anonymous):

make clear ur question

OpenStudy (anonymous):

i'm looking for the value of w

OpenStudy (anonymous):

b^2 (a^2 + a^4 + 2 a b - b^2 - 2 a^2 b^2 + b^4))/(-a^3 + a b^2 + 2 b^3)

OpenStudy (anonymous):

this is the value of w w =\[b^2 (a^2 + a^4 + 2 a b - b^2 - 2 a^2 b^2 + b^4) /(-a ^{3} + ab ^{2} +2b ^{3})\]

OpenStudy (anonymous):

may i know your solution?

OpenStudy (anonymous):

\[b^{2}-\cfrac{a*w}{b^{2}}-a^{2}-w+\cfrac{b}{a}+b = w-\cfrac{a}{b}-a \Leftrightarrow w = \cfrac{-b^{2}-a-\cfrac{a}{b}-b-\cfrac{b}{a}+a^{2}}{-2-\cfrac{a}{b^{2}}}\] work attached

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