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X^2+10x+21/x^2+8x+15
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\[\frac{x^2+10x + 21}{x^2 + 8x + 15}\]
yea
\[\frac{x^2 + 7x + 3x + 21}{x^2 + 3x + 5x + 15}\]
\[\frac{x(x+7)+3(x+7)}{x(x+3)+5(x+3)}\]
X^2+10x+21/x^2+8x+15 x^2 +10x +21 = (x+7) (x+3) x^2 +8x + 15 = (x+3)(x+5) X^2+10x+21/x^2+8x+15 = (x+7)(x+3)/ (x+3)(x+5) = (x+7)/(x+5)
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\[\frac{(x+7)(x+3)}{(x+5)(x+3)}\]
(3 (6 x^3+5 x^2+7))/x^2+X^2
x+3's cancel
Final Answer: \[\frac{x+7}{x+5}\]
|dw:1316193466008:dw|
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