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Solve. Assume the exercise describes a linear relationship. An investment is worth $3432 in 1991. By 1995 it has grown to $4132. Let y be the value of the investment in the year x, where x = 0 represents 1991. Write a linear equation that models the value of the investment in the year x. . y = -175x + 4832 b. y = -175x + 3432 c. y = 1/175 x + 3432 d. y = 175x + 3432
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4132 - 3432 = 700 1991 is x =0 1995 will be x = 4 slope is 700/4 = 175 y = 175x +3432
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