Question

what are the x-intercepts for f(x)= x^2-6x+3 ? please help!!!

Answer 1

when y:f(x)=0 u get the x intercepts
so
x^2 - 6x + 3 = 0
=> x^2 - 6x + 9 = 6
=> (x - 3)^2 = 6
=> x - 3 = sqrt of 6
=> x = \[3+\sqrt{6}\] and \[3-\sqrt{6}\]

Answer 2

thanks so much! Thats what I got but i'm doing this online thing and it kept saying it was wrong, must be an error!